[10 marks] Let Tu(x) = 2ux if 0 x 1/2 2u(1x) if 1/2 <...

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[10 marks] Let Tu(x) = 2ux if 0 ≤ x ≤ 1/2 2u(1x) if 1/2 < x < 1 = 1/2 Notice that when u = 1 we recover the Tent function (T(x)) discussed last week. Show that x = is an eventually fixed point of the function T√(x). [10 marks] Let Tu(x) = 2ux if 0 ≤ x ≤ 1/2 2u(1x) if 1/2 < x < 1 = 1/2 Notice that when u = 1 we recover the Tent function (T(x)) discussed last week. Show that x = is an eventually fixed point of the function T√(x).