Question: (10 points) Given that the function y1 = t- is a solution to the differential equation ty + (2t + 2)y' + 2y =0 t>0,

 (10 points) Given that the function y1 = t- is a

(10 points) Given that the function y1 = t- is a solution to the differential equation ty" + (2t + 2)y' + 2y =0 t>0, find a function y2 such that the pair {y1, 92} is a fundamental set of solutions to the differential equation

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