Question: (10 points) The velocity function is v(t) = t2 5t + 4 for a particle moving along a line. Find the displacement (net distance covered)


![distance covered) of the particle during the time interval [0, 5]. displacement](https://s3.amazonaws.com/si.experts.images/answers/2024/06/6666432775d5e_895666643274c4c8.jpg)



(10 points) The velocity function is v(t) = t2 5t + 4 for a particle moving along a line. Find the displacement (net distance covered) of the particle during the time interval [0, 5]. displacement = (10 points) A particle moves with a velocity of v(t) m/s along an s-axis. Find the displacement and the distance traveled by the particle during the given time interval. v(t)=t\\/f;05ts4 Displacement 2 Distance 2 (10 points) A particle moves along an saxis, use the given information to find the position function of the particle. 21(t)=t2 +4t7, v(0) = 0, 3(0) = 0 s(t)
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