10-Translate the following loop into C. Assume that the C-level integer i is held in register...

 

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10-Translate the following loop into C. Assume that the C-level integer "i" is held in register $s3, the C-level integer "j" is held in register $s5, and $s6 holds the base address of the integer "Mem" Array. Loop: sll $t1, $s3,2 add $t1,$t1, $t1, $t1, $s6 lw $t0,0($t1) bne $t0,$s5, Exit addi $s3,$s3,1 j Exit: Loop 10-Translate the following loop into C. Assume that the C-level integer "i" is held in register $s3, the C-level integer "j" is held in register $s5, and $s6 holds the base address of the integer "Mem" Array. Loop: sll $t1, $s3,2 add $t1,$t1, $t1, $t1, $s6 lw $t0,0($t1) bne $t0,$s5, Exit addi $s3,$s3,1 j Exit: Loop