$11: 26$ $$ \text { un } 5 $$ - learn.ejust.org $\equiv$ F Flag question The area of the region inside the Curve $r=6 \sin \theta$ and outside the Curve $r=2+2 \sin \theta$ is given by which integral below Select one: $$ \begin{array}{1} \int_{\pi / 6}^{5 \pi / 6) (6 \sin \theta)^{2}-(2+2 \sin \theta)^{2} d \theta \frac{1}{2} \int_{\pi / 6}^{\pi / 2} (6 \sin \theta)^{2}-(2+2 \sin \theta)^{2} d \theta \int_{\pi / 6}^{\pi / 2}(6 \sin \theta)^{2}-(2+2 \sin \theta)^{2} d \theta \end{array} $$ None $$ \frac{1}{2} \int_{-\pi / 3}^{\pi / 3}(6 \sin \theta)^{2}-(2+2 \sin \theta)^{2} d \theta $$ Previous page Next page 4 Announcements Jump to... * CS.SD.0891