A line y = 2x + 1cuts the variable pair of lines given by the equation...
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A line y = 2x + 1cuts the variable pair of lines given by the equation (ty – 1)? – t° (x – t)² 0 at the points A and B. If the segment AB subtends a right angle at the point C, then the Locus of C is - (A) 9(3x – 3y + 2)² – (x + y + 2)² = - %3D (B) (3x – 3y + 2)² – 9(x + y+2)² = - - (C) (3x – 3y + 2)² + (x – y + 2)² - (D) (3x + 3y – 2)² + (x – y + 2)² = - A line y = 2x + 1cuts the variable pair of lines given by the equation (ty – 1)? – t° (x – t)² 0 at the points A and B. If the segment AB subtends a right angle at the point C, then the Locus of C is - (A) 9(3x – 3y + 2)² – (x + y + 2)² = - %3D (B) (3x – 3y + 2)² – 9(x + y+2)² = - - (C) (3x – 3y + 2)² + (x – y + 2)² - (D) (3x + 3y – 2)² + (x – y + 2)² = -
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Given lisre is y 211 and ty txt 3D From eq S 2 5 t ... View the full answer
Related Book For
University Physics with Modern Physics
ISBN: 978-0321501219
12th Edition
Authors: Hugh D. Young, Roger A. Freedman, Lewis Ford
Posted Date:
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