Question: An excess amount of silver nitrate was added to 2.50 grams of impure barium chloride which resulted to a silver chloride precipitate. A. What

An excess amount of silver nitrate was added to 2.50 grams of

An excess amount of silver nitrate was added to 2.50 grams of impure barium chloride which resulted to a silver chloride precipitate. A. What is the mass of the precipitate formed * B. What is the percentage barium chloride in the sample?

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A The reaction of silver nitrate and barium chloride can be written as follo... View full answer

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