1-16 Differentiate. y = c cost + t'sin t Here is the step-by-step explanation, verified by an educator: Step 1 of 2 Differentiate the function y = ccost + t sint with respect to t. (y) = d dt (ccost + th sint) d = at (ccost) +- d dy (tz sint) Step 2 of 2 Differentiate the second term using the product rule of differentiation with respect to 2 dt (y) dt (ccost) + - (t2 sint) d = (cost) + (t? ) a dt (sint) + (sint)- ( t 2 ) = c(- sint) + (tz) (cost) + (sint) (2t) = -csint + t cost + 2t sint Final answer -csint + t cost + 2t sint