Question: (12 marks) 3. Number Conversion: a) (F2D)16= ( b) (10011010)2 = ( c) (197)10 )2 (8-bit binary number) d) (10111001010110)2 = D16 e) (273)s D16

(12 marks) 3. Number Conversion: a) (F2D)16= ( b) (10011010)2 = ( c) (197)10 )2 (8-bit binary number) d) (10111001010110)2 = D16 e) (273)s D16 f) (11101110100101)2 )s %3D g) (10101001)2e h) (0101010100)2e = ( i) (1011010111)2e = ( Dio %3D j) (-49)10 (8-bit two's complement) 2e 3D( k) (91)10 (8-bit two's complement) 1) (-357)10 = ( (12-bit two's complement)

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