12 question (2) are question, like 18 (2) are question and 18 are the each step.

Math 146 CL , Spnng 2017 Homework: Homework 8 (Ch. 8) ave Score: 0 6 DH pl 1 15 0139 (39 cump'ete) v ) HW Score: 78.93%, 30 78 of39 p15 (19 5.3.21 EEQuestmn new 1} In a survey 011d!) semor mommives as 3% samnm me most common you memew rmstake is to have Mme or no knuw'edge onno company Use a u no Swgmimance \\eve\\ to test the dawn mm m we popu'ation of 3H semor exemmves 45% say mauhe most common you mterwew rmstake w: to have mm or no knmu'edge of thecnmpany Iocnnmnc nuH hypothesis alternative hypothesis test statistic Psvahm condusiun abouuhe nuH nyoomosis andna' condusion mm addresses theorigina' c'aim Uscmo Psvalue method Uscmo norma' distribution as an approximation onnc binomia' distribution Identify the MH and aucmcme nypomcscs Choose the correct answer below OA. an:055 oa. HDPZDAE Hy pn55 H own. I I OE. an:045 or. HDPZDES H' p>n45 H. pn55 I|\\ Chcxm se'em your answer and men suck Check Answer 76' parts c . remammg - mom AH ' 1.191011% 0L . Spnng 2017 Homework: Homework 8 (Ch. 8) ave Score: 0 6 DH pl 1 16 0139 (39 cump1ete) v ) HW Score: 78.93%. 30 78 of39 p15 @ 5.3.21 EEQuestmn Hem c} In a survey o1 150 semor eeecmives 51 3% gamma me mos1 common jab memew m1stake is 1o nave mm or no know1edge onne company Use a u as 1gn1i1cance1eve1totesnhe c1arm1na11n me popmauon of a1 semor execmwes 45% say mauhe mos1 common jab mterwew rmstake rs 1o nave Me or no knounedge of mecompany Idennmne nuH nypomes1s a11ema11ve nypo1nes1s 1es1s1a11s11c Psva1ue conc1ds1on apouune ndu nypomesis and11na1 conc1ds1on 1na1 addresses 1neon'g1na1 c1a1m Use me Psvalue me1nod Use me norrna1d1s1n'pu11on as an approx1ma11on onne o1norn1a1d1s1n'ou11on Idenuiy me MH and a11ema11venypo1neses cnoose the correc1 answer below H. p:5 HD p:uds H. p045 H. V055 Hu F045 H. page H. pUBU H. p>UZU OC. Hup:BU OD. Hup:DED H oUZU H. prtuzu Hu p:UBU Hu p:usn H' p>DBU H. [#080 i-in p:nsn V HD p:ozo H' pn791 H' rum H. rum OE. H0 p=079| OF. HD p=n791 H' p>0791 H. p0791 Chcxm se'em ynur answer and men suck Check Answer part5 remammg- C'earAH m' ' , Math 116 0L 7 Spring 2017 Homework: Homework 8 (Ch. 8) Score: 0 2 DH pl 1 20 0139 (39 cumpiete) v ) HW Score: 76,37%, 29 78 of39 p15 (19 3.3.29: r5 Question Help t:- ln a recent court case it was toundthat during a penod ot it years est peoplewere selected lor grandqu dirty and 35% ol them were lrorn the sarne ethnicity Arnong the people eligitrle lor grandlury duty 79 5% were ot this ethnicity Use an at significance level to test the claim that the selection process is oiased against allowing this ethnicity to sit on the grandiury Identity the null hypothesis alternative hypothesis test statistic Psvalue conclusion abnutthe null hypothesis andlinai conclusion that addresses the on'pinai ciairn Use the Psvalue rnethod and the norrnai distn'oution as an approximation to the binomial distribution Which til the following is the hypmhesis Les| to he conduded" 4 HD p:n796 o HD p>u795 H' pn 796 H. p:n795 V hin p=0796 : HD p=n795 H' pn795 E hin p017 00.11D p017 HI 9:0 17 We1ghls (g) of a Random Samme 01 Candy 7 O C- H0 FR\" '7 Red B1ue Brwwn Green Yenuw 1;, O D- H0 1"\" '7 H1 0:017 0991 0791 0994 0999 0959 H. 0\"? 0902 0709 0779 0953 0919 H. WW7 0 977 0 799 0 913 0 795 0 971 0 713 0 943 0 799 0 745 0.912 0 724 0 771 0 999 0 927 0 779 0 721 0 991 0 792 0 779 0 999 0 995 0 927 0 914 0 942 0 999 0949 0713 0979 0942 0911 0 992 0 909 0 999 0 929 0 999 0959 0794 0914 0944 0771 0 793 0 911 0 979 0 934 0 935 0913 0949 0919 0944 0999 0 959 0 759 0 999 0 701 0 995 0 941 0 959 0 935 0 799 0 70d 0 905 0 934 0 729 0 973 0 719 0 729 PHM Dane CNCK m 561551 ynur answer and men CHCK CHECK Answer K? p part5 remammg - dear/>111 m1 ' Math 116 0L , Spring 2017 Homework: Homework 8 (Ch. 8) Score: 0 2 DH pl 1 21 0139 (39 cumpiete) v ) HW Score: 75,85%, 29 58 of39 p15 @ 3.3.33: 5 Question Heip c} A candy campariy makes rive dinereni coiers of candies Firid the sample pmponiori oi candies inai are green Use that resuit m Lesuhe ciairn that We at the company's candies are green Useme data in the Labia beidw the Pei/aide rnemed and a signiiicance ievei ol 0 025 a Ciick tine icon in View tine candy weigms What are me riuH and aiiernaiive hypmheses'l Hn pnii How-017 HD p>l7 H. g:ni7 H. 9:01? What is Mexesx statistic? z : u 21' (Roundto mo decirnai places as needed) What is the P-vaius Pavalue : 0334' (Roumo inree decirnai niaces as needed) What is die cariciusiari an die nuii hypothesis\" Faii to reieci ine nuii nypoinesis because we Pavaiue is iess man erequai mine signiiicance ievei ix Reecnne nuH hypnlhesis because he Pavaiue is iess inan nrequai minesignincance ievei [1 9t Faii L0 reiecnne nuii nypmnesis because ine Pevaiue is greatenhari me signiiicanceievei i1 Reject ine nuH nypmnesis because me P-vaiue is greaterthari ine signiiicance ievei a What is \\iieiinai Conciusion'l * There is not smicieni evidencek) warrari| reieciicn at me ciairn inai 17% of me cnmnariy's candies are green There is suiciem evidence in suppon me ciairn inai 17% of me cernpany's candies are green x There is suicieni evidence in wanani reieciien eiine ciairn that 17% at me company's candies are green There is riot simiciem evidencetu suppun ine ciaini max 17% enne cernpany's candies are green OUSSUUH is complete. TED D" We red iiCtUFS '0 SEE \"ICONS\" answers. Kb Mrshowms _i i > 199111146 01. , Sum!) 2017 Homework: Homework 8 (Ch. 8) ave Score: 0 0\" pl 1 26 91 39 (39 cump1ete) v ) HW Score: 69 23%, 27 of 39 p15 (:9 8.4.9-T 95 91991191 9919 1:1- A5511111911191 9 51111919 191199111 59111919 1195 119911 59199199119111 9 1191111911y 915111111199 999111911911 911919511119 9111911 9191111 19911111y 1119 111111 9119 9119111911119 11y991119595,1951519115119, P1131119, 9119 519191119111191 991191115191111191 999195595 1119 911911191 9191111 111 9 1119111191 911 1191119 11919 9 119199919119 59119, 11 i5 519199111919 59119 1111151119 1191911991111911 219 59991195 A 51111919 19119911 5919919 91119 91119111 1111 591195 1959115 111 9 1119911 19119111 91242 a 599 9119 9 519119919 99111911911 915993 599 U59 9 9 95 51911111991199191191 91191119 99991119919199 11111111911 d1splay 1919511119 9191111191 1119 59111919 15119111 9 99911911911 91 591195 1111111 9 1119911 9199191111911 210 599. Mm 99111959 19511115 51199951 9991111119 991199 9111911 1111119 1119111917 0 5191 11191991119 119.1 1119 11111111199 d1sp1ay W191 919 1119 11119911195957 0 A. H\": 11=210 599 0 11111111911 915111911 0 B. HD:11>210 599 HI \">210 599 11.: 115210 599 o c. \"9 11219 599 0119511111919T H.:11s21u 599 Te51911119=210115 >210 95% Lower N Mean SIDev Bound T F 40 242.90 54.63 . 28.35 3.81 0.000 Cl1cxm se1em ynur answer and men 1:11:11 Check Answer part5 199911119- 919911911 m1 ' , Math 116 0L s Spring 2017 Homework: Homework 8 (Ch. 8) Score: 0 4 DH pl 1 26 0139 (39 cumpiete) v ) HW Score: 75,34%, 29 38 of39 p15 @ 8.4.9-T s5 ooesnun Help in- Assumeinai a simple random sample rias oeen seiecied irom a normally dislnouied popuiaiion and lesl the given ciaim ldenliiy ine null and allemaliue nypolneses lesl siaiisiic Prvaiue and siaie ineiinai conclusion that addresses lne onginai claim in a manual on nowlo nave a number one song i is slaledlnal a song musi oe no iongerinan 2m seconds A simple random sample oi 40 cunenl nil songs iesuils in a mean lengln oizao 3 sec and a slandard deuiaiion oi 54 07 sec Use a u as signiiicance ieuei and me accompanying Minilali display loiesl lne ciaim inal ine sample is irom a ooouiaiion oi songs win a mean greaiennan 210 sec wnai do inese resuiis suggesi aooin iiie advice given in iiie manual? 0 Click the icurl to View the Minilab display wnai aie ine nypoinesesv ; H\" p>ZIUsec 3 HD u=2wsec HI \"5210 sec H. nszm sec Vi iln p:2m sec : HD ii2| sec H. pain sec ldenliiy llie lesl slalisiic l: 3 31' (Roundio two decimal places as needed) ldenliiy llie Psvaiue Tne P-vaiue is 0,001' (Round lo iniee decimal places as needed) Stale ineiinai conclusion that addresses the original ciaim chooseme correct answer below e Reiecl H0 There is insuiiicienl euidencelo supponlne ciaimlnallne sample is iiom a popuiaiion oi songs Willi a mean iengln greatertrlarl 2m sec *5 Reieci H0 There is suriicieni evidence lo supponine ciaim inaune sample is him a popuiaiion oi songs wiiii a mean lengln greatertrlarl 2m sec Xi Faii L0 ieieci H\" were is soiiicieni evidence lo suppon me ciaim inai me sample is fmrrl a popuiaiion oi songs win a mean iengin greaiennan 2m sec Fail to ieiecl Hn There is insniiicienl euidenceio suppon lne ciaim inal lne sample is irom a populalion oi songs wiln a mean iengln giealeilnan 210 sec wnai do line results suggesl aooul lne aduice given in me manual? The resuiis suggesi maLZ3B 3 seconds is me oesi song iengin The resuils suggesl inailne adiiice oi wnling a song inal musl be no iongerllian 2m seconds is noi sound advice i rne resuiis do noi suggesi inai me advice oi wniing a song inai musi oe no iongennan 2m seconds is noi sound advice The resuils are inconclusiue oecause line auerage lengln oi a nil song is conslanliy cnanging Ouesliuri is complete. Tap all We rel: indicaturs in see incurred answers. An parts snowing i . 3/ r Math 116 0L , Sprlng 2017 Homework: Homework 8 (Ch. 8) ave Score: 1 0\" pl 1 29 0139 (39 cumplete) v ) HW Score: 74,32%, 28 98 of39 p15 @ 8.4.10-T g5 Questlnn Help 1} A slrnple random sample pl 45 adulls l5 omalned irorn a normally dlslnpmed populallon and eacn person's red blood cell counl (m cells permlcrolller) l5 measured Tne sample mean ls 521 and ma sample slandam dewallon l5 0 55 Use a u as slgnlllcance level and lne glven calculalor dlsplay Lo lesl me 'liTest clalm lnal me sample ls lrom a populallon wlln a mean less man 54 wnlcn ls avalue ollen used lorlne upperllmll ollne range ol normal ualues wnal do me results suggesl aboul me sample gmup7 p 131 HI p13t D ' A T n egmes a .2. m Wu 3' s O C \"U W '31 H' u: 13' mum om no: nus mm 020 D_ H : m H \"3' , ms: IVEQY m 5sz 1m 0 n l' 1 P 2 \"as 6555 4m 2520 ma 1 ml 4 su u: 2 353 L535 2 um 32m gm m: 1.533 5 ma: 3 365 2.1m 2 m5 , m s nu ma 2,447 um um I ma 2 gas use was mm a us 2 age no. law L197 9 m 2 a2 2.2:: mg 13!: u) my 2 m :2:- m2 W2 11 no: 2 m m 1 795 1.35: 12 was 2551 m we: use 13 mu 2 ago no: nu 1350 w an 2 52 ms um L545 15 my 2 s02 1m , 7;: , m 25 m 2 sex mo ms L537 17 m 2 s57 1m] 2 7m 2 m m an 2 \"2 um um L114: 15 um 2559 m was v :29 2a m 2 522 anus ms L315 22 an 2 5m 2.2m 1721 152; 22 an I sue um um m: 2: m1 2 son ms nu mg :4 2m 2 492 um my me 25 an 2 m; m , ma , m; a m 2m 2.4m I706 ms 27 2.11: 2 m um um 2a 2.13: 2 m an LED 2-: use 2 22 7.06 v 555 , w 30 an 2 257 am: :59: um n 21214 2 .5; may 1535 1:09 52 am 2 mg m I694 um 11 am 2 n; my 1592 Vina 34 m 2441 2.9:: 1259' um 15 am 2 as am vase me as m 2m m was L506 w as 2 m m mm H05 13 m 2 229 m I655 Lm' Chcxm se'emynur answer and men suck Check Answer 1'3 1709 7'25 1M1 '595 \"04 , m m 2 .21 m ISBA L101 v , [.1 arts remammg - an Dane Math 116 0L , Sum!) 2017 Homework: Homework 8 (Ch. 8) ave Score: 0 25 OH pl 1 31 0139 (39 cump'ete) v ) HW Score: 71.24%, 27 78 of39 p15 @ 3.4.17 EEQuestmn Hen c} FormeloHr/wmg meirn nd the nun and enemauve nypmneses test stausuc :rmca' vame and drew a conc'usmn Assume mm a snnpxe random samp'e nas been se'ectedlmm a nnnnany dxstnbmed popu'atmn Answerpans ad. C'airn The mean IQ entire 0! statistics pmlessnrs is greatertnan 116 Samp'e data n :21 x : I21 5 :12 The significance \\eve' is n : U U5 Q Chck xne man to View a tame of cnhca' Ha'ues a. Cnonselne corrects nuu nypmnesws (no) and enemawe nynmnesws (H1) H0 \">115 nI p=116 V nn [IZHS H' p116 Hu [1: HS nI \"#115 nn [1) HS n' p n5 0 C. Fan to reJecnhe nuu hypothesis and do nolsuppomhedawmtnatp>116 O D. Rqect me nuH hypothesws and suppon me dawn mm [1 >115 Cthd se'em ydur answer and men suck CnecK Answer. \\/ D Math 116 0L , Sum!) 2017 Homework: Homework 8 (Ch. 8) ave Score: 0 0\" pl 1 32 0139 (39 cump1ete) v ) HW Score: 70 6%, 27 53 of39 p15 8.4.22-T g5 Questmn Hem c} Assumema1 a s1mp1e random samp1e has been se1emed andtest me gwen c1a1m Idenmy me mm and a11ema1we hypotheses test s1a1is0c Pevalue and slateme i1na1 concmsmn that addresses the ongmal daim L1s1ed hem are brain vdumes 171 cm3 of 0nre1a1ed sumeds used 171 a smdy Use a 0 01 s1gn1i1cance 1eve1 m 1es1 me dawn ma1 me poemam of brawl vemmes has a mean equal 19 1090 0 W3 052 1028 1271 107a 1071 1172 1057 1347 1090 1204 a wnax are me hynmheses" OA- Hn \"=10998cm3 05- HD 0:10998am3 H' pt10993em3 H. 0480 H. a460 V: HD pawn hI [1:480 H. mean i E1:: Identify thetesl statistic 2 922' (Round to three decimai places as needed) Identify the cnticai vaiue(s) 1 333' (Roundto three decimai piaces as needed Use a comma to separate answers as needed) State thefinai conciusion that addresses the originai ciaim Reieet ' HD. There is ounciem evidence tosupportthe ciairn thatthe rnean nurntier of definedwords is greaterthantsu Do the resuits suggest that there are more than TD nun delined words in the dictionary" The resuits are inconciusive iii it * Since many pages that were sampied have rnore than 45 words there must he more than 70 one words in the dictionary '0 There is sufficient evidence to support the ciaim that there are rnore than 70 nun words in the dictionary , There is not sufficient evidenceto support the ciairrl that there are more than 70 DDU Words in the dictionary Ouestiun is complete. Tap an the red indicaturs tu see incurred answers. 3/ D An parts snowing i t Math 116 0L , Sum!) 2017 Homework: Homework 8 (Ch. 8) ave Score: 0 2 DH pl 1 34 0139 (39 cump'ete) v ) HW Score: 70,17%, 27 37 of39 p15 @ 8.4.27-T g5 mam Hem n- The accnmpanying dala lame hsls me weigms of male coHege sludem: m kHograms, Tesme clam Ihal ma'e conege sludenls have a mean wewghl mat is '955 Ihanlhe 33 kg mean wewgm 0| "mes mme genem' popu'almn Use a u m Swgmlmance \\eve\\ Ideny me nuu hypolhesws, anemalwe hypomesis, Iesl stausmc, Fr vame, and cancmsmn Iormelesl, Assumemis is a simp'e random sample a Chck Ihe \\con Io View Ihe samule data. Whal are the mm and allemalive hypotheses" o A. Hu \"#B3kg . O E. H\": wsakg H1: II: 53 kg 0 Welgms m ma'e anege students - X ".21\" 83 k9 OC. Hu \":33kg OD. Hu:u:83kg H' p83kg FuH dale sen :1 Person Weighl Persun Weighl t M 17 80 Z 97 '3 55 3 74 I5 54 4 92 20 73 5 59 21 77 6 TI 2 74 7 57 23 74 3 92 24 54 9 67 25 54 1n EB 25 54 H 57 27 55 '2 31 28 71 '3 EU 29 55 M 70 30 75 15 58 31 74 '5 53 32 34 Prmt Dane Chcxm se'em ynur answer and men suck Check Answer part5 remammg- C'earAH m' ' , Math 116 0L , Spring 2017 Homework: Homework 8 (Ch. 8) ave Score: 0 2 DH pl 1 34 0139 (39 cumpiete) v ) HW Score: 70.17%, 27 37 of39 p15 8_4_27-T E5 Question Help Q The accpmpanying data lapie iisls the weights of male college sludeiits in kilograms Test lhe claim that male college sludents have a mean weighl mat is less than the El: kg mean weighl or males in lhe general popuialipn Use a u in signiiicance level ldentiry lhe null hypothesis ailematwe hypothesis test stalistic FL value and canciusipn lorlhelesl Assumelhis is a simple random sample a Click the icon \\0 View the sample data What are the null and altematiue hypotheses" hu \"#szg Hu ll:82kg H' p=szi82i120 H. 1mm Calculate the test statistic 79 190' (Round mhyee decrmar praees as needed) What is the range M va'ues iorthe PavaMe? Cnnnse the current answer be'mv X D 050 20 U U1 n55 H [#045 I I OE. anZDAS or. HDPZDES H' p>n45 H. prnss Chcxm se'em ynur answer and men suck Check Answer part5 remammg- crearAn m' ' , Math 1316 0L - Spring 201? Homework: Homework 8 (Ch. 8) Score: 0 of1 pt 1 18 of 39 (39 complete) 1' p HW Score: 69.23%, 2? of 39 pts (8) 8.3.21 5E Question Help {1' In a survey of 145 senior executives, 48.3% said that the most commonjob interview mistake is to have little or no knowledge of the company. Use a [1.05- signiticance level to test the claim that in the population of all senior executives, 45% say that the most commonjob interview mistake is to have little or no knowledge of the company. Identify the null hypothesis, altemative hypothesis, test statistic, Pvalue, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the Pvalue method. Use the normal distribution as an approximation of the binomial distribution. Identify the null and altemative hypotheses. Choose the correct answer below. A H0: p=.55 . 3 H0: p=.45 H1: p<.55 h1: p .: h0: .v: h1zp>U.55 H1:p#0.45 E H0: p=.45 . 3 H0: p=.55 H1Zpr.45 H1:p#0.55 The test statistic is 2 = -. (Round to two decimal places as needed.) ' X Enter your answer in the answer box and then click Check Answer. if!) b pans 2 remaining _ ClearAll CheckAnswer l {