1.222 129 60 ft Record the time elapsed from the start to the 10 ft and...

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1.222 129 60 ft Record the time elapsed from the start to the 10 ft and 90 ft timing gates 60+ Subj 1 a Upright 2 pt Trial b Subj 1 a 3 pt b Time at 10 ft Time at 90 ft Elapsed Time 10 - 90 ft elay 1.292 te ini 3.875 Goft 3.785 airit to saoquc Subj 1 a Baseball 1.148 pindot gniste teshib nieu 3.726 b tremo Subj 2 a Upright 2 pt 1.013 M 3.153x2414 b Subj 2 a 3 pt wa oril puig br1.121 3.237 so fripil emotiwa b no A Subj 2 a Baseball puig boss 1.082 3.164 b 3.990 _disini) hista Isisc ojni pulq bre -08 0 else primit br olo no mised tripil artt Subj 3 a Upright 2 pt 1.791 4.056 b Subj 3 a 3 pt b 1.170 3.894 Subj 3 a Baseball 1:461 4.267 b 1:463 4.425 Subj 4 a Upright 2 pt b 1.432 3.058 Subj 4 a 3 pt 1.037 3.095 enimi b to quote al p _ 1.330 3.429 b 3.204 (lec Subj 4 a Baseball Subj 5 a Upright 2 pt b Subj 5 a 3 pt b Subj 5 a Baseball b Inlo Then select the fastest trial for each subject using the 3 different stances, calculate the individual's velocity during the first 10 ft displacement, the next 80 ft displacement, and the overall velocity through 90 ft. Also, calculate the acceleration experienced from the first interval to the second interval. Velocity 10 ft Velocity 10 - 90 ft 60 Velocity 90 ft 60 Accel 1 to 2 interval Subj 1 Upright 2 pt Subj 1 3 pt Subj 1 Baseball Subj 2 Upright 2 pt 2.14. Subj 2 3 pt Subj 2 Baseball Subj 3 Upright 2 pt Subj 3 3 pt Subj 3 Baseball Subj 4 Upright 2 pt Subj 4 3 pt Subj 4 Baseball Subj 5 Upright 2 pt Subj 5 3 pt Subj 5 Baseball Subject 2 2 point position 0 2013 10 60 1.013-0 3.153-1.013 2.14] 0 1.013 3.153 V60 = 60ft 3.153 19.03 Velocity = 10ft 50 ft 1.013 2.14 9.87 23.36 Subj acceleration = V50-V10-23.36-9.87 13.49 8.5569 = = 2.0835065 1.576 8.561 1.222 129 60 ft Record the time elapsed from the start to the 10 ft and 90 ft timing gates 60+ Subj 1 a Upright 2 pt Trial b Subj 1 a 3 pt b Time at 10 ft Time at 90 ft Elapsed Time 10 - 90 ft elay 1.292 te ini 3.875 Goft 3.785 airit to saoquc Subj 1 a Baseball 1.148 pindot gniste teshib nieu 3.726 b tremo Subj 2 a Upright 2 pt 1.013 M 3.153x2414 b Subj 2 a 3 pt wa oril puig br1.121 3.237 so fripil emotiwa b no A Subj 2 a Baseball puig boss 1.082 3.164 b 3.990 _disini) hista Isisc ojni pulq bre -08 0 else primit br olo no mised tripil artt Subj 3 a Upright 2 pt 1.791 4.056 b Subj 3 a 3 pt b 1.170 3.894 Subj 3 a Baseball 1:461 4.267 b 1:463 4.425 Subj 4 a Upright 2 pt b 1.432 3.058 Subj 4 a 3 pt 1.037 3.095 enimi b to quote al p _ 1.330 3.429 b 3.204 (lec Subj 4 a Baseball Subj 5 a Upright 2 pt b Subj 5 a 3 pt b Subj 5 a Baseball b Inlo Then select the fastest trial for each subject using the 3 different stances, calculate the individual's velocity during the first 10 ft displacement, the next 80 ft displacement, and the overall velocity through 90 ft. Also, calculate the acceleration experienced from the first interval to the second interval. Velocity 10 ft Velocity 10 - 90 ft 60 Velocity 90 ft 60 Accel 1 to 2 interval Subj 1 Upright 2 pt Subj 1 3 pt Subj 1 Baseball Subj 2 Upright 2 pt 2.14. Subj 2 3 pt Subj 2 Baseball Subj 3 Upright 2 pt Subj 3 3 pt Subj 3 Baseball Subj 4 Upright 2 pt Subj 4 3 pt Subj 4 Baseball Subj 5 Upright 2 pt Subj 5 3 pt Subj 5 Baseball Subject 2 2 point position 0 2013 10 60 1.013-0 3.153-1.013 2.14] 0 1.013 3.153 V60 = 60ft 3.153 19.03 Velocity = 10ft 50 ft 1.013 2.14 9.87 23.36 Subj acceleration = V50-V10-23.36-9.87 13.49 8.5569 = = 2.0835065 1.576 8.561