Question: 13. How many grams of solid PbCl2 form when 15.3g of NaCl(aq) reacts with 60.8g of Pb(NO3)2(aq) according to the balanced chemical equation shown below?

13. How many grams of solid PbCl2 form when 15.3g of NaCl(aq) reacts with 60.8g of Pb(NO3)2(aq) according to the balanced chemical equation shown below? 2NaCl(aq)+Pb(NO3)2(aq)2NaNO3(aq)+PbCl2(s)[balanced] Molar Mass: NaCl58.44g/molPb(NO3)2331.21g/molPbCl2278.11g/mol A. 36.4gPbCl2 B. 43.8gPbCl2 C. 51.1gPbCl2 D. 87.5PbCl2

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