Question: 14 E A proton initially has = 4.01 -2.01 +3.0k and then 4.0 s later has = -2.01 - 2.0 +5.0k (in meters per second).

14 E A proton initially has = 4.01 -2.01 +3.0k and then 4.0 s later has = -2.01 - 2.0 +5.0k (in meters per second). For that 4.0 s, what are (a) -> the proton's average acceleration davg in unit-vector notation, (b) the magnitude of davg, and (c) the angle between dave and the positive direction of the X axis

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