Question: 18. We wish to construct a byte-addressable memory system with a capacity of 2,048 bytes using 64x8 RAM chips. How many address lines must go
18. We wish to construct a byte-addressable memory system with a capacity of 2,048 bytes using 64x8 RAM chips. How many address lines must go to each RAM chip? 5 4 6 7
19. We wish to construct a byte-addressable memory system with a capacity of 2,048 bytes using 64x8 RAM chips. How many address lines must be decoded to generate the chip select inputs for the RAM chips?
| 5 |
| 4 |
| 6 |
| 7 |
20. Which of the following are advantages for Big endian over Little endian?
| High-precision arithmetic is faster. |
| Little endian machines are faster at certain string operations. |
| Big endian is more natural for people most people. |
| Some types of encoding, such as Huffman and LZW, is faster on Big endian machines. |
21. Using the MARIE instruction set on page 252 of your book, convert the following assembly code to binary: LoadI 101
| 0001 0000 0110 0101 |
| 1101 0000 0101 0101 |
| 0001 0000 0101 0101 |
| 1101 0000 0110 0101 |
22. Using the MARIE instruction set on page 252 of your book, convert the following assembly code to binary: Halt
| 0111 0000 0000 0000 |
| 1000 0000 0000 0000 |
| 1111 0000 0000 0000 |
| 0101 0000 0000 0000 |
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
