196 Pre-Lab: Equilibrium (E11-11) Examine the configuration at the right. There's a diagonal rod that's held in place by the tension of a rope or cable in a way that produces a right-angle. The rod is attached to a pivot point at the lower left. T The goal might be to either determine the mass or weight of the rod OR the location of the rod's "center of mass" (CM), depending on what's available. This time, derive an equation which represents the location of the rod's CM, as a diagonal distance (along - * - the rod) from the pivot, if these other value are given. Given: g = grav.accel. T = tension (in newtons) measured by the spring scale at the top left. m = mass of hanging mass on right rod "A" w/ length = L L = length of rod mrod = mass of diagonal rod m x = horizontal distance from rod hinge to point where 4.. ...... the hanging mass is connected y = vertical distance from rod hinge to point where m rod the hanging mass is connected 0= implied angle with the horizontal Requested: r'em = distance pivot to rod CM X Equations: ET=0 [T = torque from tension = +yT cos 8 =- x Tw = torque from hanging mass = -xW W = mg Trod = - * rod W rod Wrod = Mrod8 Xrod = rem COs O Derivation: I'cm = Equation #5 Physics 105L Lab Instructor. S. T.Randall Fall 2022