1A)

A newsgroup is interested in constructing a 99% confidence interval for the proportion of all Americans who are in favor of a new Green initiative. Of the 554 randomly selected Americans surveyed, 356 were in favor of the initiative. Round answers to 4 decimal places where possible. SHOW WORK

i.-With 99% confidence the proportion of all Americans who favor the new Green initiative is between _________and_______.

ii.If many groups of 554 randomly selected Americans were surveyed, then a different confidence interval would be produced from each group. About ________percent of these confidence intervals will contain the true population proportion of Americans who favor the Green initiative and about _______percent will not contain the true population proportion.

1B)

Out of 400 people sampled, 244 had kids. Based on this, construct a 95% confidence interval for the true population proportion of people with kids.

Give your answers as decimals, to four places SHOW WORK

1C)

We wish to estimate what percent of adult residents in a certain county are parents. Out of 100 adult residents sampled, 69 had kids. Based on this, construct a 90% confidence interval for the proportion p of adult residents who are parents in this county.

Express your answer in tri-inequality form. Give your answers as decimals, to three places.

________< p <_______Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.

P= _______ ________