Question: . 1a**b=sqrt(|ab|) , on the set Q . 2a^(**)b=alnb , on the set {xinR:x>0} . 3a**b is a root of the equation x^(2)-a^(2)b^(2)=0 , on
.\
1a**b=\\\\sqrt(|ab|), on the set
Q.\
2a^(**)b=alnb, on the set
{xinR:x>0}.\
3a**bis a root of the equation
x^(2)-a^(2)b^(2)=0, on the set
R.\ 4 Subtraction, on the set
z.\ 5 Subtraction, on the set
{ninz:>=0}.\
6a**b=|a-b|, on the set
{ninz:>=0}.

is not an integer.) Thus, z is not closed under *. 1ab=ab, on the set Q. 2ab=alnb, on the set {xR:x>0}. 3ab is a root of the equation x2a2b2=0, on the set R. 4 Subtraction, on the set z. 5 Subtraction, on the set {nz:0}. 6ab=ab, on the set {nz:0}
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
