Question: 1.Which choice is correct for exercise 1 and why it is correct? p = 0.1 confidence level=95% Formular: confidence interval = p+ z VP(1-)p =0.1+1.96
1.Which choice is correct for exercise 1 and why it is correct?

p = 0.1 confidence level=95% Formular: confidence interval = p+ z VP(1-)p =0.1+1.96 Vo.1(0.9) 1300 =10% +5.88% = [4.12%:15.88%] Then after giving Leos questions some thought, you recommend to him that he send the mailing to a specific number of guests. Enter the number of guests as an integer, (e.g., 5). Round if necessary. Based on the confidence interval for the proportion, the maximum percentage of people who are likely to respond to the discount offer (at the 95% confidence level) is 15.88%. So, if 15.85% of people were to respond for 200 rooms, how many people should Leo send out the survey to? Simply divide 200 by 0.1588 to get to the answer: Leo needs to send out the survey to at most 1,259 past customers. ( 200 = 0.1586 - 1259.44 # 1. 259 Leo is pleased with your work. He tells you to relax and enjoy the resort. HW. next week Exercise1:GMW Automotive GMW is a German auto manufacturer that has regional sales subsidiaries throughout the world, Arturo Lopez heads the Mexican sales division of the company s Latin American subsidiary. GMW earns additional profit when customers choose to finance their car purchase with a GMW financing package. Arturo has been asked to submit a report to the 6MW CEO in Germany about the percentage of GMW customers who opt for financing Arturo has asked you, a new member of the division sales team, to devise a way to estimate this percentage. You take a random sample of 64 cars sold in the Mexican sales division, and find that 13 of them, or about 20.3 fo, opted for GMW financing. If you want to be 95% confident in your report to Mr. Lopez, you should tell him that the percentage of all Mexican customers opting for GMW financing falls in the range: A. * from 12.0% to 28.6% B. * from 10.4%to 30.2% c . * from 15.1% to 25.5% D. * You do not have sufficient information to solve this problem n = 64 p = 20.3% confidence level=95%
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