//1)Write method evenMumbers(), which takes a single int[]

//parameter array, 'numbers'.Call evenNumbers() in main with

//a argument array of size at least 10, that has some even

//numbers. Count the # of even numbers in the array and

//return the count. Hint: use the remainder operator, %, to

//determine if the number at index i is even or odd.

//Remember 10 % 2 == 0, because 2 divides 10 evenly 5 times.