Question: ( 2 0 points ) As shown in the figure, the motor drives the taut conveyor belt at a speed of v 0 = 2

(20 points) As shown in the figure, the motor drives the taut conveyor belt at a speed of v0=2ms. The angle
between the conveyor belt and the horizontal plane is =30. Now a workpiece with a mass of m=10kg is
gently placed on the bottom of the belt. After a period of time, the workpiece is sent to a platform at a height of
h=2m. The dynamic friction coefficient between the workpiece and the belt is known to be =322. Apart from
this, no other dissipation is considered. (Note that the dynamic friction is fk=Fn, where Fn is the normal force
exerted by the workpiece on the conveyor belt. The static friction is equal to or less than the dynamic friction.)
(a) Calculate the speed of the workpiece when it reaches the platform (8 points).
(b) Calculate the change in mechanical energy of the workpiece (6 points).
(c) Find the extra electric energy consumed by the motor due to the transmission of the workpiece. (Hint: In
the presence of friction f bewteen two objects, some mechanical energy is transformed to thermal energy
W=|fs|, where s is the relative displacement of the two objects.)(6 points)
( 2 0 points ) As shown in the figure, the motor

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