$[2*10$pts$]$ VII. Use substitution to find:

$1.$

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{(lnx{)}^2}{x}dx$

$=lnxdw=\frac{1}{x}dx$

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{(lnx{)}^2}{x}dx={\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}{v}^{2}dv=\frac{v^3}{3}+C=\frac{(lnx{)}^3}{3}+C$

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{(lnx{)}^2}{x}dx=\frac{(lnx{)}^3}{3}+C$

${\displaystyle \underset{0}{\overset{1}{}}}x{e}^{x^2}dx$