Question: 2 1 1 X 8 5 ( atomic mass = 2 1 0 . 9 ) undergoes alpha decay. Assuming all the released energy is

211X85(atomic mass =210.9) undergoes alpha decay. Assuming all the released energy is in the form of kinetic energy of the alpha particle ( atomic mass =4.00260 u) and ignoring the recoil of the daughter nucleus (207X83 atomic mass =207) find the speed of the alpha particle

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