$2\mathrm{.}1$ Determine $\frac{dy}{dx}$ in each of the following cases. $($It is NOT necessary to simplify$)$

$2\mathrm{.}1\mathrm{.}1y=arctan(sec2x)-e^{x^2}$

$2\mathrm{.}1\mathrm{.}2y=\sqrt[\phantom{2}]{cot2x*lnx}[sin(cos\sqrt[\phantom{2}]{x^2+1}){]}^0$