Question: 2 4. Using trig substitution, the integral / 11: da: would become I: '332 -2 (a) [8111 0:16 cos 0 (b) / sin2 6 d6

6 d6 (C) [311129 d6 cos2 9 (d) / sin2 6 cos

0016 (e) none of these If you have an integral with the

substitution x = 2 sin 0 and after integration get the answer

2 4. Using trig substitution, the integral / 11: da: would become I: '332 -2 (a) [8111 0:16 cos 0 (b) / sin2 6 d6 (C) [311129 d6 cos2 9 (d) / sin2 6 cos 0016 (e) none of these If you have an integral with the substitution x = 2 sin 0 and after integration get the answer 0 - 4 cos 0 + C, what is the answer in terms of x? (a) arcsin (3) - 4V4-x2 + C (b) sin (3) - 4V4-x2 + C (c) - arcsin () - 2V4-x2+ C (d) - arcsin () - V4-x2 + C (e) none of these2. For / V21? 1dx,we would use a: = (a) sing (b) tan (c) sect? (d) (2036 (e) none of these

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