$(25)3.$ Fresh air at $60\%$ RH and $20C$ will be fed to the dryer after being heated to $120C$ and will leave the dryer at $80C$ and $80\%RH$

a$)$ The amount of water removed from the product in the dryer is $kg$ water$/$kg $KH$

b$)11465k\frac{g}{h}$ of fresh molst alr is fed to the dryer under intet cohaitlons and $500k\frac{g}{h}$ of $35\%$ molsture product is dried, the resulting moisture content of the product leaving the dryer will be $\%$

C$)$ The dew point of the air leaving the dryer is $......"$C$.$

$)=(101,325kPz$