$2.(5\text{'})$ For the following code, explain under what circumstance$($s$)$ the action of the while loop would be skipped:

$```$

num$=$input$(\text{'}$Enter a number: $\text{'})$;

while num $>=0$

fprintf$(\text{'}$You entered a $\%\mathrm{.}1$f$!$

$\text{'},$ num$)$

num$=$input$(\text{'}$Enter a number: $\text{'})$;

end

disp$(\text{'}$That is all.$\text{'})$

$```$