$25$

Formula

$1$ point

Assume that Mars is $1\mathrm{.}524$ AU from the Sun in the red circular orbit shown in the figure. If the perigee velocity needed to initiate the black transfer orbit from Earth to Mars is $32\mathrm{.}60$ kilometers per second, what is the apogee velocity at the top of the black transfer orbit in kilometers per second? HINT: $(\frac{v_a}{v_p})=(\frac{r_p}{r_a})$ and $1AU=149\mathrm{.}6$ EE$9$ meters or $93\mathrm{.}5$EE $6$ miles