Question: 2. Assume m > 0, b 2 0, and * 2 0. Explain why the roots of ms* + bs + h have real part

 2. Assume m > 0, b 2 0, and * 2

2. Assume m > 0, b 2 0, and * 2 0. Explain why the roots of ms* + bs + h have real part less than or equal to zero; and that the real part equals zero only when b = 0 (no damping). What happens to the solutions of mi + bit kr = 0 as t - too? (The answer will depend on whether b = 0.)

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