Question: 2. Calculate the instantaneous slope for the given function or curve at the specified point. a) 2:2 my + y2 = 3 at (1,1) M

 2. Calculate the instantaneous slope for the given function or curveat the specified point. a) 2:2 my + y2 = 3 at(1,1) M y =1n(ex+1+ a753? at (0:1) c) y = (cos Ifat (0,1) (Dy =(\\/)1\" at (111) \f3. Use implicit differentiation or the

2. Calculate the instantaneous slope for the given function or curve at the specified point. a) 2:2 my + y2 = 3 at (1,1) M y =1n(ex+1+ a753? at (0:1) c) y = (cos If at (0,1) (Dy =(\\/)1\" at (111) \f3. Use implicit differentiation or the inverse function theorem to calculate the derivative. You must derive your answer; you cannot simply state the formula. f(x) = arcsin(x) = sin (x)4. The function f(:r:) = 2:: + cos(:t:) (shown right) is invertible. (a) What is the value of f'1(1)? Hint: f(0) = 1. (b) Use the inverse function theorem to calculate % [f ' 1 (13)] at 17 = 1

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