Question: 2 . Consider a magnetic disk with a sector size 5 1 2 bytes, 4 0 0 tracks per surface, 1 0 0 sectors per

2. Consider a magnetic disk with a sector size 512 bytes, 400 tracks per surface, 100 sectors per track, 4 double-sided platters, average seek time of 10 milliseconds, and average latency time (i.e., average rotational delay) is 8 milliseconds. You can assume that 1 block contains 2 sectors and each track has an equal number of sectors to keep the question simple. Answer the below questions.
a) What is the capacity of a track in bytes?
b) What is the capacity of a cylinder in bytes?
c) How many cylinders does the disk have?
d) What is the capacity of the disk in bytes?
e) If 1 track of data is transferred during 1 rotation of the disk platter, compute the block transfer time in milliseconds. You can assume that time required to rotate the disk platter once is equal to \(2^{*}\)(average latency time).
2 . Consider a magnetic disk with a sector size 5

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