Question: 2 Demonstrating a Problem in Both NP and co - NP In this problem, you will explore a specific problem that belongs to both the
Demonstrating a Problem in Both NP and coNP
In this problem, you will explore a specific problem that belongs to both the complexity classes NP and
coNP Specifically, you will demonstrate why the Exact Cover Problem fits into both of these classes.
You will also review the definitions of NP and coNP and explain how Exact Cover satisfies the conditions
for membership in both classes.
Definitions
NP Nondeterministic Polynomial Time: A decision problem is in NP if a solution or certificate
can be verified in polynomial time. That is given a proposed solution, there exists a polynomialtime
algorithm that can check whether the solution is correct.
coNP: A decision problem is in coNP if a no answer or a counterexample can be verified in
polynomial time. In other words, coNP is the complement of NP where instead of verifying a solution,
you verify that no solution exists or that a counterexample is valid
The problem we will focus on a somewhat easier variant of the Ordered Exact Cover Problem, which
asks the following:
Input: A set U of n distinct elements and a collection S of subsets of U
Output: Is there a subset of S such that the union of the sets in this subset exactly covers U with no
element of U being covered more than once? That is is there a subset T S such that all elements
of T are pairwise disjoint and S
t in T t U
Promise: The set S is ordered such that for all i i Si Si iff Si Si and
max Si max Si
Questions
Verifying Ordered Exact Cover in NP:
Show that the Exact Cover Problem is in NP by explaining how to verify a solution in poly
nomial time.
Specifically, describe how, given a set U and a polynomially bounded collection of subsets S
you can provide a certificate of an exact cover a set of subsets whose union equals U and verify
that no element of U is covered more than once.
Explain why this satisfies the definition of NP
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