2. For the titration of 250 mL of 0.200 mol L-1 HF(Ka = 6.3 x 10-4) with...
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2. For the titration of 250 mL of 0.200 mol L-1 HF(Ka = 6.3 x 10-4) with a solution of 1.00 M NaOH:
a) What is the pH at the half-equivalence point?
b) What is the pH at the equivalence point?
Expert Answer:
Answer rating: 100% (QA)
The reaction is between a weak acid HF and a strong base NaOH So this is an examp... View the full answer
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