Question: 2 int-string input (Please enter an integer: .) If Statements Using Elif and Else In the previous question, we used an if statement that contained

 2 int-string input ("Please enter an integer: .) If Statements Using

2 int-string input ("Please enter an integer: .) If Statements Using Elif and Else In the previous question, we used an if statement that contained an else branch. Sometimes, however, we have more than one condition we wish to test. This could be done using multiple if statements but can often also be accomplished using the if-elif-else form: if conditioni: code if conditionl true [code_if condition1 true...] elif condition2: code if condition2 truc [code if condition2_true...1 code if neither condition true [code if neither condition true...] Here, if condition1 evaluates to False, then Python will test condition2. There can be more than one elif and the else branch is optional. For example, this code will print Monty' if x is 1, 'Python' if x is 2, 'Flying' if x is 3, and Circus otherwise: if x1 elif x == 2: elif x3: elac: printl 'Monty") printt Python) print('Flying') printl Circus') Prompt the user to enter an integer, and then print 'negative' if the entered number is negative, 'zero' if it is o and 'positive' if it is positive. You should use the if-elif-else form

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