Question: 2. Is the function /(x) = = continuous on the closed interval [-1, 1] ? Draw its graph illustrating its continuity or discontinuity. Solution: Step

![interval [-1, 1] ? Draw its graph illustrating its continuity or discontinuity.](https://s3.amazonaws.com/si.experts.images/answers/2024/06/6667eada3776d_3626667eada16444.jpg)
2. Is the function /(x) = = continuous on the closed interval [-1, 1] ? Draw its graph illustrating its continuity or discontinuity. Solution: Step 1: The function /(x) needs to be verified continuous at the open interval (-1, 1) by creating its table of values or simply knowing its restrictions with regard to its domain. A. Table of values X-values f() = = y-values -0.999 0 0.9999 B. Domain restriction of the function: Step 2: The function /(x) needs to be continuous at the left endpoint [-1]. a. Evaluate the function /(x) = =atx = -1 b. Find lim. () c. What did you observe between the values of /(-1) and lim, f(x) ? Step 3: The function /(x)needs to be continuous at the right endpoint [1]. a. Evaluate the function f(x) = = at x = 1 b. Find lim () =_ c. What did you observe between the values of f(1) and lim f(x) ? Conclusion: Illustrate the graph: X 3. Check whether the function f(x) =is continuous at x = 4. Sketch its graph illustrating its continuity or discontinuity. 4. Prove whether the function /(x) =vx-2 is continuous on the closed interval [2, 4] or not? Sketch the graph illustrating its continuity or discontinuity
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