Question: 2 K + 2 H 2 O 2 KOH + H 2 From previous step, you know 1 9 . 5 5 g of potassium

2K+2H2O2KOH+H2
From previous step, you know 19.55g of potassium react and the solutions absorbs 90,100J of energy.
What is the enthalpy, in kJmol, of the reaction?
Hrn=kJmol
Hint: Remember qrxn=-qsoln
Enter either a + or - sign AND the magnitude.
 2K+2H2O2KOH+H2 From previous step, you know 19.55g of potassium react and

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