Question: Let f(x) = 4x + 4x + 5. Then according to the definition of derivative f'(-4) is the limit as a tends to of

$-et ( f(x)=4 x^{2}+4 x+5 ). Then according to the definition of derivative ( f^{prime}(-4) ) is the limit as ( x ) ten$

$Let ( f(x)=left{begin{array}{ll}x^{2}+-4 & x<0 -4 & x geq 0end{array}ight. ) (A) Sketch the graph of ( f ), and$

Let f(x) = 4x + 4x + 5. Then according to the definition of derivative f'(-4) is the limit as a tends to of the expression The value of this limit is x < 0 x > 0 (A) Sketch the graph of f, and when you're done, place a "1" in the box: Let f(x) = x +-4 -4 (B) Find the value of where f is discontinuous. If there is no value, enter 'NONE'. x-values = (C) Find the value of a where f is not differentiable. If there is no value, enter 'NONE'. x-values =

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