Question: 2. Let f(x) = x3 + 6x - 36x + 1 a) List all critical points, c, from the first derivative such that f'(c)=0

2. Let f(x) = x3 + 6x - 36x + 1 a)

2. Let f(x) = x3 + 6x - 36x + 1 a) List all critical points, c, from the first derivative such that f'(c)=0 b) For each of the values in part a, calculate f"(c) c) According to the second derivative test for extrema, what do the results mean?

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