$2$

Multiple Choice $0\mathrm{.}5$ points

${\displaystyle \underset{1}{\overset{2}{}}}\frac{(lnx{)}^2}{x^3}dx$

$\frac{3}{16}-\frac{1}{8}(ln2{)}^2-\frac{1}{8}ln2$

$\frac{3}{16}-\frac{1}{8}(ln2{)}^2$

$\frac{1}{8}-\frac{1}{8}(ln3{)}^2-\frac{1}{8}ln3$

$\frac{1}{8}(ln2{)}^2-\frac{1}{8}ln2$