$(2$ points$)$

The differential equation

$y-4y^7=(y^6+6x)y^{\text{'}}$

can be written in differential form:

$M(x,y)dx+N(x,y)dy=0$

where

$M(x,y)=$

$,$ and

$N(x,y)=.($To receive credit both answers must be correct.$)$

The left$-$hand side $M(x,y)dx+N(x,y)dy$ becomes an exact differential if it is divided by $y^7.$ Integrate the resulting equation to obtain a solution of the differential equation:

$=C$