Question: ( 2 PT ) Subtract 3 7 . 6 9 0 5 5 6 from 1 0 1 5 8 ' 0 2 ' '

(2 PT) Subtract 37.690556 from 10158'02''. Give your answer in degrees minutes and seconds.
(2 PT) A vertical angle is measured as -2132'14''. What is the equivalent zenith angle.
A Traverse course AB has a bearing of S8841'38''W and a horizontal distance of 142.3 ft .
a.(2 PT) What is the bearing of BA?
b.(2 PT) What is the azimuth of AB?
c.(2 PT) What is the latitude and departure between A and B?
Two survey points, A and B , are on the slope of a hill. The slope distance between the two points is
257.4 ft . If the zenith angle from A to B is 8814'35'', calculate:
a.(4 PT) The elevation difference between A and B.
b.(4 PT) The horizontal distance between A and B.
( 2 PT ) Subtract 3 7 . 6 9 0 5 5 6 from 1 0 1 5

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