${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}(2^t+e^{})dt=$

$(A)\frac{2^{t+1}}{t+1}+\frac{e^{+1}}{+1}+C$

$(B)\frac{2^t}{ln2}+e^{}t+C$

$(C)\frac{2^t}{ln2}+e^{}+C$

$(D)2^{t}ln2+\frac{e^{+1}}{+1}+C$

$(E)2^{t}ln2+e^{}t+C$