2) The content of PC in the basic computer is 1B0 (all numbers are in hexadecimal) and the initial value of E is 1. The content of AC is 701B. The content of memory at address 1B0 is 7080. The content of memory at address 080 is 15AC. The content of memory at address 5AC is 7BFFThe content of memory at address BFF is 0000. 15 points (a) List the sequence of micro-operations for the instruction cycle (fetch, decode. execute) of this instruction. 15 points (b) Show the contents of the registers (PC, AR, DR. AC, IR, E, LSC) after the positive transition of each clock pulse for each timing signal: 115 points (c) If any memory location(s) contents change because of the execution of the above instruction, list them: I5 pointsl Initial 1 Be 5AC BFF