Question: 2) The function fx (x; 0) =- 2Vx e-0vx for x > 0 is a valid pdf. If X1 = 4, X2 = 49, X3

2) The function fx (x; 0) =- 2Vx e-0vx for x

2) The function fx (x; 0) =- 2Vx e-0vx for x > 0 is a valid pdf. If X1 = 4, X2 = 49, X3 = 9, X4 = 9 are a random sample from this distribution, find the maximum likelihood estimator of 0

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