Question: 2) The ship has the features as displacement (8700+ stdnt no last two digit) MT , LBP=198 m. LCG-1,3 m and VCG= 10,7 m. There

2) The ship has the features as displacement

2) The ship has the features as displacement (8700+ stdnt no last two digit) MT , LBP=198 m. LCG-1,3 m and VCG= 10,7 m. There are 5 warehouses in the ship. The cargo of wheat as SF=1,2 m /MT will be loaded as full capacity. The ship will be loaded in sea water (1025 kg/m). The total FSM (Free Surface Moment) is (5400+stdnt no last two digit) MT.m. You can use the stability booklet table at the below for the calculations. (signs are taken as from mastory to fwd (-) and to aft (+)) CAPASITY WEIGHT VCG LCG MOMENT WAREHOUSES (m) MOMENT (m) (+) (-) (m) (MT) Loaded NO :1 5474,0 9,5 -45,0 NO: 2 5480,0 9,5 -28,0 NO :3 5580,0 9,8 -5,0 NO: 4 5575,0 9,8 20,0 NO: 5 5560,0 9,8 30,0 8700+ -1,3 stdnt no SHIP 10,7 last two digit a) How many tons of cargo can be loaded each compartment, and what is the GM, trim and drafts of the ship, after loading? (10 p.) b)How much ballast should be taken in the tank (LCG|-(80+ stdnt no last one digit) m, because the ship will be even keel? (10 p.) STABILITY BOOKLET Draft Disp. TPC MTC LCF LCB KM (m) (MT) (MT/cm) (MTm/cm) (m) (m) (m) 8,00 25.820,50 38,71 449,87 -2,56 -5,64 11,11 8,25 26.795,70 39,24 467,40 -2,32 -5,61 11,16 8,50 27.782,90 39,70 482,77 -2,07 -5,57 11,19 8,75 28.779,50 40,02 493,50 -1,89 -5,54 11,22 9,00 29.783,40 40,27 501,86 -1,68 -5,50 11,24 9,25 30.792,90 40,48 508,78 -1,47 -5,47 11,27 9,50 31.807,40 40,66 514,89 -1,26 -5,41 11,29 9,75 32.826,30 40,82 520,34 -1,03 -5,36 11,30 10,00 33.848,90 40,97 525,35 -0,84 -5,34 11,31 3) A ship 150 metres long arrives at the mouth of a river with drafts 5,5 m Fwd, and 6,4 m Aft MCT 1 cm 200 tonnes m. TPC 15 tonnes. Centre of flotation is 1,5 m aft of amidships. The ship has then to proceed up the river where the maxi-mum draft permissible is 6,0 m. It is decided that SW ballast will be run into the forepeak tank to reduce the draft aft to 6,0 m. If the centre of gravity of the forepeak tank is (60+student no last one digit) metres forward of the centre of flotation, find the minimum amount of water which must be run in and also find the final draft forward. (15 p.) 2) The ship has the features as displacement (8700+ stdnt no last two digit) MT , LBP=198 m. LCG-1,3 m and VCG= 10,7 m. There are 5 warehouses in the ship. The cargo of wheat as SF=1,2 m /MT will be loaded as full capacity. The ship will be loaded in sea water (1025 kg/m). The total FSM (Free Surface Moment) is (5400+stdnt no last two digit) MT.m. You can use the stability booklet table at the below for the calculations. (signs are taken as from mastory to fwd (-) and to aft (+)) CAPASITY WEIGHT VCG LCG MOMENT WAREHOUSES (m) MOMENT (m) (+) (-) (m) (MT) Loaded NO :1 5474,0 9,5 -45,0 NO: 2 5480,0 9,5 -28,0 NO :3 5580,0 9,8 -5,0 NO: 4 5575,0 9,8 20,0 NO: 5 5560,0 9,8 30,0 8700+ -1,3 stdnt no SHIP 10,7 last two digit a) How many tons of cargo can be loaded each compartment, and what is the GM, trim and drafts of the ship, after loading? (10 p.) b)How much ballast should be taken in the tank (LCG|-(80+ stdnt no last one digit) m, because the ship will be even keel? (10 p.) STABILITY BOOKLET Draft Disp. TPC MTC LCF LCB KM (m) (MT) (MT/cm) (MTm/cm) (m) (m) (m) 8,00 25.820,50 38,71 449,87 -2,56 -5,64 11,11 8,25 26.795,70 39,24 467,40 -2,32 -5,61 11,16 8,50 27.782,90 39,70 482,77 -2,07 -5,57 11,19 8,75 28.779,50 40,02 493,50 -1,89 -5,54 11,22 9,00 29.783,40 40,27 501,86 -1,68 -5,50 11,24 9,25 30.792,90 40,48 508,78 -1,47 -5,47 11,27 9,50 31.807,40 40,66 514,89 -1,26 -5,41 11,29 9,75 32.826,30 40,82 520,34 -1,03 -5,36 11,30 10,00 33.848,90 40,97 525,35 -0,84 -5,34 11,31 3) A ship 150 metres long arrives at the mouth of a river with drafts 5,5 m Fwd, and 6,4 m Aft MCT 1 cm 200 tonnes m. TPC 15 tonnes. Centre of flotation is 1,5 m aft of amidships. The ship has then to proceed up the river where the maxi-mum draft permissible is 6,0 m. It is decided that SW ballast will be run into the forepeak tank to reduce the draft aft to 6,0 m. If the centre of gravity of the forepeak tank is (60+student no last one digit) metres forward of the centre of flotation, find the minimum amount of water which must be run in and also find the final draft forward. (15 p.)

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