$2.$ When the cylinders are placed in the unknown liquid, the force probe measures$0\mathrm{.}834$Nfor the Aluminum cylinder and$1\mathrm{.}474$Nfor the Lead cylinder. Use the same algebraic expression from part $1$ to calculate the buoyant force.FB$$on Al cylinder:FB$$onPbcylinder: $3.$ Use the buoyant forces to calculate the density of the liquid for each cylinder.$[$NOTE:$=$gVT$+$Vm$+$v$$V$2$m$$gV$2$T$$Giventhe complexity and tedium of such a calculation, we will skip it$.]$ Density of liquid based on Al trial$=710\mathrm{.}5070$kg$/$cm$$c$$XDensity of liquid based on Pb trial $=$ Further testing identifies the liquid as $2,2,4-$trimethylpentane, which has a density of$692$kg$3$m$3.$ Hopefully, your answers are reasonably close to this.

I dont understand how I got these xs wrong please explain