2. Write code in Matlab or Python (or both!) to computer = pi - 27 with p 665857 and y = 470832 in single and in double precision. Explain the reason for the unexpected result you get. Is any of those two numbers correct? Remark: in MatLab you can force a variable to represent a single-precision floating point number using the instruction single, 08.pmsingle(665857). In Python there is no such thing and you will have to call Numpy eg, with import numpy. After that, you can use instrutions like p umpy, float32 (665857) to force a number to be stored in 32 bits format. 3. Repeat the previous exercise with p = 10864, - 18817 and 0 -1 +27 4. Repeat the previous exercise with p - 10" = -2 and r p +