${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{2^x}{\sqrt[\phantom{2}]{2^x+1}}dx=$

$A.\frac{ln\sqrt[\phantom{2}]{2^x+1}}{ln2}+C$

$B.2\sqrt[\phantom{2}]{2^x+1}+C$

$c.(ln2)\sqrt[\phantom{2}]{2^x+1}+C$

$D.ln2\sqrt[\phantom{2}]{ln(2^x+1)}+C$

$E.\frac{2}{ln2}\sqrt[\phantom{2}]{2^x+1}+C$