Question: 20. Given event T1, T2, T3, and D with p(D)=0.05, p(T1|D)=p(~T1|~D)=0.9, p(T2|D)=p(~T2|~D)=0.8, p(T3|D)=0.9 and p(~T3|~D)=1, find p(T1u T2UT3) if p(T1NT2)=0.05, p(T1NT3)=0.01, and T2 and

20. Given event T1, T2, T3, and D with p(D)=0.05, p(T1|D)=p(~T1|~D)=0.9, p(T2|D)=p(~T2|~D)=0.8,

20. Given event T1, T2, T3, and D with p(D)=0.05, p(T1|D)=p(~T1|~D)=0.9, p(T2|D)=p(~T2|~D)=0.8, p(T3|D)=0.9 and p(~T3|~D)=1, find p(T1u T2UT3) if p(T1NT2)=0.05, p(T1NT3)=0.01, and T2 and T3 are mutually exclusive.

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