Question: (20 Points) Using the Bisect and False Position functions, compute the roots of the function f(x) = 0.0025e3* cos(x) + 0.15 and the number of

 (20 Points) Using the Bisect and False Position functions, compute the

(20 Points) Using the Bisect and False Position functions, compute the roots of the function f(x) = 0.0025e3* cos(x) + 0.15 and the number of iterations required as described below. Use an error tolerance of 0.001%. Hint: Modify your functions to include the number of iterations as an output to the functions. a. Plot the function between 0 and 5. b. Compute the root between 0 and 4 for both methods. Display a table in the command window with the following columns: Method, Root, and Iterations. Display the root with 10 decimal places. Just above the table, use an fprintf statement to display a statement such as: "Using 0 and 4 as the bounds". After the table, explain the difference in the number of iterations between the two methods (use fprintf statement). c. Create the table again but use 4 and 5 as the bounds. After the table, explain the difference in the number of iterations between part band c for the False Position method (use fprintf statement), d. Plot all solutions (in the figure from part a) using: Bisection part b: a red asterisk False Position part b: a red square Bisection part c: green asterisk False Position part c: a green square

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