[2+1 da (a) Let u r+1 = (b) Then du = 3x dx or du =...

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[₁2²√³+1 da (a) Let u r³+1 = (b) Then du = 3x² dx or du = r² dr (c) If z = -1, then u = (-1)³ + 1 = 0. (d) If z = 1, then u = = (1)³ + 1 = 2 (e) Now substitute [₁2²√³+1 da (a) Let u r³+1 = (b) Then du = 3x² dx or du = r² dr (c) If z = -1, then u = (-1)³ + 1 = 0. (d) If z = 1, then u = = (1)³ + 1 = 2 (e) Now substitute

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